Re, the required minimum make contact with stress pmin = two.74 MPa. The MS37452 supplier maximum speak to stress pmax that the extrusion roller can bear devoid of plastic deformation is as follows [11]: pmax = 1 – ( d 2 ) / D 3+( d four ) s2 D (2)where s2 is definitely the yield strength with the roller sleeve, s2 = 835 MPa, D is the outer diameter of your roller sleeve, and D = 1800 mm; pmax = 259.42 MPa was obtained. The connection between the interference and also the speak to stress amongst the roller shaft along with the roller sleeve is as follows [11]: = pd( C1 C + 2) E1 E2 (3)exactly where C1 = [d2 + d2 ]/[d2 – d2 ] – , C2 = [ D2 + d2 ]/[ D2 – d2 ] + , and where may be the 1 1 interference, p is the make contact with stress between the roller shaft plus the roller sleeve, C1 is definitely the rigidity coefficient with the roller shaft, C2 is the rigidity coefficient of the roller sleeve, E1 may be the elastic modulus of the roller shaft, E2 may be the elastic modulus in the roller sleeve, may be the Poisson’s ratio on the roller shaft, is definitely the Poisson’s ratio of your roller sleeve, and d1 may be the inner diameter in the roller shaft; hence d1 = 200 mm. The relationship amongst the maximum tension on the roller shaft 1max , the maximum stress from the roller sleeve 2max , along with the speak to stress pf is as follows [8]: 1max = 2max =pf a(4) (5)pf c where a and c are the roller shaft and roller sleeve Fexinidazole custom synthesis coefficients, respectively.d a = [1 – ( d1 ) ]/2 = 0.49, c = [1 – ( D ) ]/2 = 0.28. d The interference between the roller shaft plus the roller sleeve = 1.45 mm, receive the corresponding speak to pressure pf = 69.05 MPa, pmin pf pmax , which meets the requirements of make contact with pressure. The maximum stress of the roller shaft 1max = 140.92 MPa s1 = 930 MPa, and the maximum anxiety of the roller sleeve 2max = 246.61 MPa s2 = 835 MPa. It may be seen that the interference = 1.45 mm meets the strength requirement.2.2. Extrusion Force of Extrusion Roller The extrusion force on the extrusion roller ought to be considered according to the law of material compression and rebound traits. Following entering the compression zone, the material is extruded by the extrusion roller, plus the extrusion force increases with all the decrease on the stress angle in a specific range. When the stress angle is zero, the extrusion force reaches the maximum worth. Right after the material enters the rebound zoneAppl. Sci. 2021, 11,5 ofat a certain angle, the extrusion force gradually decreases to zero. The horizontal tension equation at any point on the surface with the extrusion roller is as follows [8]: pc ln1-0 1- 1-0 1-1 n 1 np(, ) =1 – (two ||)m 0p ln c( – )k 1 – (two ||)m – 0 s-(six)exactly where p(,) is definitely the horizontal tension at any point with the extrusion roller in MPa ( could be the stress angle, = Z/B, Z is the distance from a point around the roller surface towards the vertical surface inside the extrusion roller), 0 will be the angle in the starting of compression zone, D is definitely the extrusion roller diameter in mm, computer will be the certain pressure of material in MPa, may be the relative density in the end of the rebound zone, will be the angle in the end of the rebound zone, s may be the relative density at the end of compression zone, and 0 will be the initial relative density. The calculation formula is 0 = 0 /, exactly where 0 is the initial density, is compaction density of material in kg/m3 , is definitely the stress angle relative density from the corresponding material layer, n may be the compression curve element, and m will be the axial distribution coefficient of pressure, exactly where m 1. The material made use of was silica sand in this a.
